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29 de may. de 2015 · Given the sequence 123456789: You can insert three operations (+ +, − −, × ×, / /) into this sequence to make the equation = 100. My question is: is there a way to solve this without brute force? (I tried to represent it as a graph but I'm unsure where to go from there.) With brute force: 123 − 45 − 67 + 89 = 100 123 − 45 − 67 ...
31 de dic. de 2019 · $\begingroup$ Some questions which seem a bit related: How can I prove this odd property?, Why is $\frac{987654321}{123456789}$ almost exactly $8$?, Why is $\frac{987654321}{123456789} = 8.0000000729?!$ and maybe some of the questions linked there. $\endgroup$ –
It's not entirely coincidence: 246,913,578 = 2·123,456,789. So of course that's what you get if you multiply by 5 or divide by 2. But I find it surprising that that's what you get if you multiply by 7, and I think there's something else at work here. It's also suspicious that none of those numbers are divisible by 3.
123456789大写分别是：壹、贰、叁、肆、伍、陆、柒、捌、玖。 1、以中文的形式表示数字，在开具发票、收据的时候经常用到，尤其在金融领域。但数字的中文表示和其它语言有很大的不同，如中文以每4个数字（万）为一个小的分隔。
11. We can see that in the decimal system each of $12345679\times k$ $ (k\in\mathbb N, k\lt 81, k\ \text {is coprime to $9$})$ (note! not $123456789$) has every number from $0$ to $9$ except one number as its digit numbers . $$12345679\times 2= [0]24691358$$ $$12345679\times 4= [0]49382716$$ $$12345679\times 5= [0]61728395$$ $$12345679\times 7 ...
20 de ene. de 2017 · Thus the ratio. 987654321 123456789 is very close to 8 1. Addendum: If you consider the rational 10 81 = 0.123456790123456790⋯ where the 8 are overwritten by carries, you observe the more "regular" product. 9 ⋅ 123456790 = 1111111110. And considering. 8 ⋅ 987654320 = 987654320. we have. 9 ⋅ 987654320 = 8888888880.
In the first 1 billion digits of π π, I found two instances of 123456789 123456789, but no instances of 1234567890 1234567890. Here's a simple example. In the first billion digits, there were 10049 10049 instances of 12345. 12345. There were 969 969 instances of 123456 123456. There were 97 97 instances of 1234567 1234567.
24 de mar. de 2018 · Then the results of B and C is multiplied and the result is 123456789. What number did A choose? For clarity: Let the number chosen by A be a, the number chosen by B be b, and the number chosen by C be c. We then have: $$(b^2 + a)(c^2\cdot a)= 123456789.$$ How would you solve this problem without a calculator?
7 de may. de 2017 · I just started typing some numbers in my calculator and accidentally realized that $\frac{123456789}{987654321}=1/8$ and vice versa $\frac{987654321}{123456789}=8.000000072900001$, so very close to $8$. Is this just a coincidence or is there a pattern behind this or another explanation?
4 de oct. de 2016 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
